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Fluid force on vertical side of tank the weight density of water is 62.4 trapezoid
Fluid force on vertical side of tank the weight density of water is 62.4 trapezoid









The density of the ethylene glycol is constant.

fluid force on vertical side of tank the weight density of water is 62.4 trapezoid

If the depth of the liquid is 0.8 m, what is the pressure at the bottom of the tank? Approach: Use the equation for pressure as a function of depth in an incompressible fluid: P = P∞ + ρ gh. The air space at the top of the closed vat is maintained at 110 kPa. ⎠ ⎝ 1000 Pa ⎠ ⎦ ⎣ P = 120 kPa 4-4 Answer A vat in a chemical processing plant contains liquid ethylene glycol at 20oC. Solution: At an assumed temperature of 20✬, the density of mercury (from Table B-6) is ρ Hg = 13,579 kg/m3 The pressure in an incompressible fluid as a function of depth is P = Patm + ρ Hg gh ⎡ ⎛ 0.3048 m ⎞ ⎛ 1 kPa ⎞ ⎤ P = 100 kPa + ⎢(13,579 kg/m3 )( 9.8 m/s 2 ) ( 6in.) ⎜ ⎟⎜ ⎟⎥ ⎝ 12 in. The mercury is at room temperature (20✬). If atmospheric pressure is 100 kPa, what pressure is the manometer reading (in kPa)? Approach: Use the equation for pressure as a function of depth in an incompressible fluid: P = Patm + ρ gh. ⎠ ⎠ Answer 4-3 In a manometer containing liquid mercury, the height is read as 6 in. Solution: At an assumed temperature of 70✯, the density of water (from Table B-6) is ρ H 2O = 62.2 lbm/ft 3 The pressure in an incompressible fluid as a function of depth is P = Patm + ρ gh ⎛ ⎜ 1 lbf lbf ⎛ lbm ⎞⎛ ft ⎞ = 14.7 2 + ⎜ 62.2 3 ⎟⎜ 32.2 2 ⎟ ( 725ft ) ⎜ in.

fluid force on vertical side of tank the weight density of water is 62.4 trapezoid

Approach: Use the equation for pressure as a function of depth in an incompressible fluid: P = Patm + ρ gh. Assuming atmospheric pressure is 14.7 lbf/in.2, calculate the pressure in the reservoir at the base of the dam. ⎠ ⎦ ⎣ Answer P = 19.0 lbf in.2 4-2 Hoover dam stands at a height of 725 ft above the Colorado river. Solution: At an assumed temperature of 70✯, the density of water (from Table B-6) is ρ H 2O = 62.2 lbm/ft 3 The pressure in an incompressible fluid as a function of depth is P = Patm + ρ gh ⎡ ⎛ ⎞ ⎛ 1ft 2 ⎞ ⎤ 1lbf = 14.7 lbf in.2 + ⎢( 62.2 lbm/ft 3 )( 32.2 ft/s 2 ) (10 ft ) ⎜ 2 ⎟⎜ 2 ⎟⎥ ⎝ 32.2 lbm ⋅ ft/s ⎠⎝ 144in.

fluid force on vertical side of tank the weight density of water is 62.4 trapezoid

4-1 If atmospheric pressure is 14.7 lbf/in.2, what is the pressure at a depth of 10 ft of water? Approach: Use the equation for pressure as a function of depth in an incompressible fluid: P = Patm + ρ gh.











Fluid force on vertical side of tank the weight density of water is 62.4 trapezoid